CSAT, IAS 2015. UPSC 2015

CSAT DAILY MISSION #14

Read the following passage and answer the questions that follow:

Four families decided to go for picnic to Banarasi Bagh and agreed to meet a place called Narhi before moving for the picnic. One family has no kids, while others have at least one kid each. Amongst the families with kids, at least one kid goes to the picnic. The following information is available about the families:

1. The family with two kids came just before the family with no kids.
2. D, who does not have any kids, came just before C’s family.
3. P and his wife reached last with their only kid.
4. Q is a husband, although not D’s husband.
5. C’s daughter and A’s daughter go to the same school.
6. B came before D but not A, and she is a good singer.
7. R stays farthest from Narhi, and he is also a good singer.
8. S was worried because his only child, his daughter, had thrown up during the journey.

Question 1

Who among the females arrived third?

(A) P

(B) R

(C) B

(D) D

Question 2

Which is a correct matching of husband and wife?

(A) B and D

(B) R and D

(C) S and P

(D) A and P

Question 3

Whose daughters go to the same school?

(A) S and P

(B) B and D

(C) A and P

(D) R and D

Question 4

Whose family definitely has more than one kid?

(A) Q

(B) S

(C) A

(D) C

Question 5

Who arrives second among the males?

(A) Q

(B) S

(C) A

(D) C



SOLUTIONS TO DAILY CSAT MISSION # 15

1. (D) 2. (C) 3. (C) 4. (A) 5. (C)

Explanations
1. In any cube/cuboid, each side will always have four adjacent sides and another side opposite to it.
The Yellow side is opposite to the Green side. So, both these sides will be adjacent to all the other four colours i.e. The four sides adjacent to Green are Blue, Orange, Red and Black. The four sides opposite to Yellow will also be Blue, Orange, Red and Black.
Now, consider the Blue side. It is adjacent to Green and Yellow (from above). And it is adjacent to Orange and Red (given in question). So, this means all four adjacent sides to Blue are found and the only side remaining (i.e. the Black side) must be opposite to it.
Two pairs of opposite have been found (Blue-Black and Green-Yellow). This leaves the Orange and Red sides as the third set of opposite sides.
Now, all three statements are true, which means the answer is “None of these”.

2. There are 4 small squares on each side. So, total number of squares = 4*4 + 3*3 + 2*2 + 1*1 = 30. (If there were six smaller squares on each side, the total number of squares would be 6*6 + 5*5 + ….. + 2*2 + 1*1. Whatever is the number, add all squares from 1 to that number’s square).

3. It is given that Rohini’s maternal uncle is same as the girl’s maternal uncle’s maternal uncle. It implies that girl’s maternal uncle and Rohini are siblings. This in turn means Shubha is the daughter of Rohini.
Capture

4. The only possible arrangement of all the data is the following, for a total of seven ladies.

 

Capture

5. If Ajay reached at 9:45, then Bhargav reached 13 minutes later at 9:58. Menaka’s arrival time cannot be found out. But since she reached the earliest, and Bhargav reached after Ajay, it can be concluded that Bhargav reaches the last among the three.


Comments

2 responses to “CSAT DAILY MISSION #14”

  1. 1. D
    2. B
    3. C
    4. A
    5. A

  2. DBAAA

Leave a Reply

Your email address will not be published. Required fields are marked *