CSAT DAILY MISSION #28

Guys, it was a very busy weekend for us, and all the three CSATs of Saturday, Sunday and Monday are all coming today.

Question 1

Of the are 200 employees in a company, 40% are graduates and 80% are diploma holders. If 30% are graduates and also hold a diploma, then how many are neither graduates nor diploma holders?

(A) 60

(B) 40

(D) 20

Question 2

At a dinner party, every two guests used a bowl of rice between them, every three guests used a bowl of dal between them and every four guests used a bowl of meat between them. If there were 65 dishes altogether, how many guests were at the party?

(A) 60

(B) 65

(D) None of these

Question 3

A bus starts from city X. The number of women in the bus is half the number of men. In city Y, 10 men leave the bus and five women enter. Now, the number of men and women is equal. In the beginning, how many passengers entered the bus?

(A) 15

(B) 30

(D) 45

Question 4

If the price of milk falls down by 20%, by how much can a consumer increase his consumption so that the amount he spends does not change?

(A) 20%

(B) 25%

(D) 21%

Question 5

A man goes from P to Q on foot and comes back from Q to P via taxi. He takes 16 hours to complete the whole journey. But if he covers the entire journey by taxi only, he takes four hours less. How many hours will he take to complete the entire journey if he goes and comes only on foot?

(A) 20

(B) 24

(D) 25

SOLUTIONS TO DAILY CSAT MISSION # 29

1. (A) 2. (B) 3. (C) 4. (B) 5. (A)

Explanations
1. Let the total marks be ‘x’. So, 62% of x = 372 i.e. (62/100)*x = 372.This gives ‘x’ = 600.
Then, (294/600)*100 = 49%. So, 294 is 49% of of 600.

2. W and Y cannot play together. So, (A) and (D) are ruled out. C and Z cannot play together. So, (C) is also ruled out.

3. (D) is ruled out because it does not have (B). (A) is ruled out because B and W cannot play together. (B) is ruled out because C and Z cannot play together.

4. If three of the four spots are taken by the three males A, B and C, then only the fourth spot is available to a girl. There are four girls. But because B is there, W cannot play in the team. And because C is also there, Z cannot play in the team either. So, the fourth member can be taken in two ways only: either X or Y.

5. HCF of 408 and 312 is 24. So, the minimum number of sections will be formed when students are arranged into classes of 24 each.
Sections containing only boys = 408/24 = 17.
Sections containing only boys = 312/24 = 13.
Total sections = 30.