Read the following information carefully and answer the two items that follow.
The city crime branch has caught 6 criminals suspects A, B, C, D, E and F and the police have interrogated them. The police knows that among the 6 criminals, 2 are pickpockets, 2 are chain snatchers and 2 are kidnappers. Each criminal is associated with the other criminal of the same crime. The six suspects provided the following statements. In every statement, the police know that the first sentence is false and the second one is true.
A: “I am with B and F. I know nothing about kidnapping.”
B: “I am with F and C. I know nothing about pickpocketing.”
C: “l am with A and E. I know nothing about kidnapping.”
D: “I am with A and C. I know nothing about chain snatching.”
E: “I am with D and F. I know nothing about pickpocketing.”
F: “I am with D and A. I know nothing about chain snatching.”
Question 1
Who is C’s partner and what do they commit?
(A) F ; pickpocketing
(B) D ; pickpocketing
(C) F ; chain-snatching
(D) D ; chain-snatching
Question 2
Who are the kidnappers?
(A) B and E
(B) A and E
(C) C and F
(D) B and D
Question 3
In a particular row of seats in a cinema hall, Vikram is 15th from the left and Naveen is 18th from the right. If they interchange their positions, Naveen will be 25th from the right. What is the total number of seats in that row?
(A) 36
(B) 37
(C) 38
(D) 39
Question 4
Two friends Kavya and Lakshmi are talking to each other face to face. It is the time of the day before sunset. If Lakshmi’s shadow is exactly to her right, which direction is Kavya facing?
(A) East
(B) West
(C) North
(D) South
Question 5
Suresh is born on 21st February of a non-leap year. Suresh is older to Chetan by exactly one year and 4 days. If 21st February is a Monday, on which day Chetan is born?
(A) Saturday
(B) Monday
(C) Friday
(D) Sunday
N.B. Please note that the official timings for publication of these questions is 11 am daily.
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SOLUTIONS TO DAILY CSAT MISSION #96 (CLICK)
1. (C) 2. (A) 3. (B) 4. (B) 5. (C)
Explanations
1. The speed of 1st cyclist = 3 km/hr = 3 X 1000/60 m/min = 50 m/min.
The speed of second cyclist = 6 km/hr = 100 m/min
The relative speed = 100 – 50 = 50 m/min
In order to meet the first cyclist again, the second cyclist needs to gain 1 full round. The time required to gain 1 full round = distance / relative speed = 400/ 50 = 8 min.
2. Initially it had 98% water and 2% non-water matter from a total of 3000gm.
The weight of non-water matter = 3000 X 2/100 = 60gm
When it is kept in sun, the weight of non-water matter remains the same while water loss occurs.
But as per the question, now the 60gm of non-water matter = 4% of the fruit.
If 4% = 60gm, 100% = 60 X 100 / 4 = 1500gm.
Note: It may seem a little unbelievable that while the net weight has gone down by 1500 gm, the percentage of water has decreased by only 2%. But you have to see that the ratio of non-water to water has doubled. From being 2/98, it has become 4/96. This can only have happened if the numerator has been doubled or the denominator has been halved. Since the non-water part (numerator) has stayed the same, the only conclusion is that the denominator (water portion) has become half. Don’t doubt your mathematically-arrived solution in the exam, by thinking that it doesn’t make sense.
3. Let the original price be ‘a’.
Tarun paid Kiran 1.5a and Charan paid Tarun 1.2 x (1.5a) = 1.8a
It is given that Tarun paid Rs.360. so 1.8a = 360 which gives ‘a’ as 200.
4. Let ‘a’ be the speed of boat and ‘b’ be the speed of river.
Speed upstream = a – b and speed downstream = a + b.
a – b = 15/6, a + b = 33/6 (because speed = distance/time)
subtracting both the equations, 2b = 33/6 – 15/6 = 18/6 = 3.
So b = 1.5 km/hr.
5. The numbers can be of three types: 56X, 5X6 and 6XY
In the first case, X = {0,1,2,3,4,5,7,8,9}
In the second case, X = {0,1,2,3,4,5,7,8,9}
In the third case, X = {0,1,2,3,4,5,7,8,9} and Y = {0,1,2,3,4,5,7,8,9}
The possible numbers are: 1st case = 9 ; 2nd case = 9 ; 3rd case = 9 X 9 = 81
The total numbers possible = 9+9+81 = 99.
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