CSAT, IAS 2015. UPSC 2015

CSAT DAILY MISSION #61

Question 1

Four bells first begin to toll together at 11:55:00 am and then at intervals of 6,7,8 and 9 seconds respectively. At what time will they toll together again?

(A) 12:00:04 am

(B) 12:00:04 pm

(C) 12:03:24 pm

(D) 12:03:34 pm

Question 2

What is the minimum number of colours required to paint the following figure such that no two colours are adjacent to each other?

Capture

(A) 3

(B) 4

(C) 5

(D) 6

Question 3

In 2009, a man was required to pay 20% of his income as tax in Argentina. In 2010, the rules changed, and now he was required to pay 2000 pesos and 5% of his earning in excess of 10000 pesos. If both his income and the amount of tax he was required to pay had not changed from 2009 to 2010, what was his income in either year?

(A) 16000 pesos

(B) 15000 pesos

(C) 12000 pesos

(D) 10000 pesos

Question 4

What is the probability that three people selected at random will be born of different days of the week?

(A) 48/49

(B) 2/3

(C) 30/49

(D) 36/49

Question 5

Examine the following statement:

The first step in treating addicts is to re-establish their lost ties, for which a continuous personal attention should be paid to the addicts under treatment.

Two assumptions numbered 1 and 2 are given below. Which of them is/are implicitly understood from the above statement?

1. Addicts under treatment respond better when shown personal interest.
2. Addiction causes relationships to strain.

(A) Only assumption 1 is implicit.

(B) Only assumption 2 is implicit.

(C) Both assumptions are implicit.

(D) Neither assumption is implicit.



SOLUTIONS TO DAILY CSAT MISSION # 62

1. (A) 2. (C) 3. (C) 4. (D) 5. (B)

Explanations
1. Lowest marks are in Hindi by F; English by D; Maths by B; Science by C; Social Studies by F; Sanskrit by C; Physical Education by F. C and F have lowest marks in two or more subjects.

2. The total marks are A – 525; B – 468; C – 412; D – 437; E – 474; F – 361. So, A has the highest overall.

3. The total marks are 600. 75% of this is 450 marks. A, B and E have more than 450.

4. Required percentage = 64/85 * 100 = 75.3%.

5. Total marks obtained by all the students = 345. So, average = 345/6 = 57.5.


Comments

4 responses to “CSAT DAILY MISSION #61”

  1. CBDCA

  2. 1.C
    2.A
    3.D
    4.C
    5.B

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