CSAT DAILY MISSION #50

Question 1

Prism Cinema has six gates for entry and exit named P,Q,R,S,T and U. Only one of S or U is open on weekdays (Monday to Friday). P is closed on Saturday. Only one of gates P,Q or R opens at any one point of time. If U is closed, then so is T. In this context, which of the following statements is true?

(A) On Saturday, exactly three gates are open.

(B) On Saturday,at least five gates are open.

(D) None of these.

Question 2

Consider the following statements:

1. All members of Tina’s family are engineers.
2. Some members of Tina’s family are govt employees.
3. No govt employee is corrupt.

Which of the following conclusions can be drawn from the above statements?

(A) Some members of Tina’s family are corrupt.

(B) There are some engineers not from Tina’s family who are corrupt.

(D) No engineer is corrupt.

Read the information given below and answer the questions that follow:

Six books named A,B,C,D,E and F are kept one over the other in a pile, not necessarily in that order. There are two books between B and D, but B is not above D. E is second from top and next to A. There are two books between A and F.

Question 3

Which is second from bottom?

(A) A

(B) B

(D) F

Question 4

Which of the following is definitely a representation of three consecutive books in the pile?

(A) EAB

(B) DFC

(D) None of these

Question 5

Two bottles whose volumes are in the ratio 4:3 are filled to half and a third with milk respectively. The bottles are then filled to the brim with water. If both bottles are now emptied into a vat that had nothing in it, what is the ratio of milk to water in the vat?

(A) 5:7

(B) 3:4

(D) 2:3

SOLUTIONS TO DAILY CSAT MISSION # 51

1.(D) 2.(A)(B)(C)(D) 3.(B) 4.(D) 5.(D)
Sorry for question 2. All options are correct.

Explanations
B is fourth to the left of D.
F is B’s neighbour. This means there are two possibilities that arise: Either F is to the immediate left of B or to the immediate right of B. The two scenarios are:

E is third to the right of F. But in Case 2, D becomes third to the right of F. So, Case 2 is discarded.

E is placed third to the right of F in Case 1, and now, because H is his neighbour, there are again two scenarios to consider: Either H is to the immediate left of E or to the immediate right of E. These two scenarios are:

It is given that D is not the neighbour of H, so Case 1.1 becomes rejected.

Now, A is the neighbour of D. So, again, there are two scenarios to consider: Either A is to the immediate left of D or to the immediate right of D. These are represented as:

In Case 1.2.2, the remaining two i.e. C and G will end up as neighbours. But this cannot happen as per the question, and Case 1.2.2 is discarded.

Finally, in Case 1.2.1, C is not the neighbour of A (as per the question), and so G will become the neighbour of A. The final arrangement is:

5. When C and G interchange positions, the arrangement becomes: