Question 1
A circle of 1 metre radius is drawn inside a square as shown in the figure:
What is the area of the shaded portion?
(A) (4 – π)
(B) (1 – π/2)
(C) 1/4(1 – π)
(D) (1 – π/4)
Question 2
Consider the following statements about six villages A,B,C,D,E and F:
1. F is 1 km to the west of D.
2. B is 1 km to the west of E.
3. A is 2 km to the north of E.
4. C is 1 km to the east of A.
5. D is 1 km to the south of A.
Which of the following three villages are in a straight line?
(A) A,B,C
(B) B,C,D
(C) C,D,E
(D) None of these
Read this information and answer the questions that follow:
Eight people P,Q,R,S,T,U,V and W are sitting around a circular table. W is second to the right of P and third to the left of Q. R is sitting between P and V. Q and T are not sitting opposite to each other.
Question 3
Assuming everyone has sat, who of the following could have sat third to the left of S?
(A) R
(B) W or Q
(C) U
(D) Cannot be determined because position of S is unknown.
Question 4
If T is not adjacent to W, which of the following could be a combination of three people sitting one after the other?
(A) S,U,Q
(B) P,T,W
(C) Q,T,S
(D) R,P,T
Question 5
A survey was conducted on a sample of 1000 people with reference to their knowledge of Maithili, Kannada and Odia. The results are presented in the following Venn diagram:
The ratio of the number of people who do not know any of the three languages to the number of people who know all the three languages is
(A) 1/27
(B) 1/25
(C) 1/550
(D) 175/1000
SOLUTIONS TO DAILY CSAT MISSION # 67
1. (B) 2. (C) 3. (D) 4. (C) 5. (C)
Explanations
1. Let the total capacity of the cistern be 36 litres.
If A fully fills it in 18 minutes, then A fills 2 litres per minute.
If B fully fills it in 9 minutes, then B fills 4 litres per minute.
If C fully empties it in 6 minutes, then C empties 6 litres per minute.
So, when A and B both are opened, they fill the cistern at 6 litres per minute. And when C is also opened, then the cistern gets filled at 6 litres per minute and empties also at 6 litres per minute i.e. the level of liquid remains the same.
2. When he arranges so that he has 38 bangles remaining after forming a square, let the number of rows (which is also the number of columns) be ‘a’.
When he arranges so that he needs 25 bangles to form a square, let the number of rows (which is also the number of columns) be ‘b’.
Let the number of bangles he has now be ‘x’.
Given, x – (a*a) = 38 and (b*b) – x = 25. So, (b*b) – (a*a) = (25 – x) – (x – 38) = 63.
Since he has increased the number of rows by 1, b = (a + 1) i.e. (b-a) = 1.
Now, we know that b*b – a*a = (b + a)(b – a). Putting these values from above, 63 = (b + a)(1), which gives (b + a) = 63. So, (b + a) = 63 and (b-a) = 1. From this, b = 32 and a = 31.
So, x = (a*a) + 38 = 999.
3. Let the number of unmarried women be ‘x’. So, total number of women = unmarried women = married women = x + 10.
The total number of people = (x + 10) + (16 children) = x + 26.
As per the question, 15(x + 26) = 22(x + 10) + 8*16, which gives ‘x’ as 6.
4. Let Z = 100. So, X = 80 and Y = 72. So, percentage by which Y is less than X = (X – Y)/X * 100 = 10%.
5. Let the SP of each goat be ‘x’.
So, CP of the goat sold for 10% profit = 100x/110 = 10x/11.
And, CP of the goat sold for 10% loss = 100x/90 = 10x/9.
Total CP = 200x/99.
Total SP = 2x = 198x/99.
Since CP > SP, Mehh suffered a loss. Loss percentage = (CP – SP)/CP * 100 = (2x/99)/(200x/99)*100 = 1%.
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