Similarly for this question as well first we need to put e in the last so the initial 4alphabet abab similarly last four alphabet eded are there and the for the rest of the sequence count the number of b d and c you will find b 3 times c 3 times and similarly d 3 times hence we need to have b c d all one times hence answer would be b c d e.
Why won’t it be c? ababa, bcbcb, and so on?
Yar yeh bta do koi please
C it is !
Considering the 2020 cutoff , what number of questions would be ideal to attempt ?
Last time attempted almost 92 , was out by 0.67 marks , I was speculating ideal attempts given difficulty level similar to 2020 ! Any insights ?
Not going with any pre set number but I feel attempting less can also be risky because vague questions me you can never really assess how many you’ll end up marking correct (as per the actual keys). Around ~90 hi probably, for me...
Looking at my score it made me feel I should have attempted less , but I second you on not attempting anything less than 90 .
80-85 is my zone. anything below or above results in suboptimal score. But i am thinking of going without any fixed number in mind. I feel upsc is trying to dissuade us from making blind guesses both in pre as well as mains. That's why they have started asking tough questions and trapping tukka experts, pattern decoders.Considering the 2020 cutoff , what number of questions would be ideal to attempt ?
Last time attempted almost 92 , was out by 0.67 marks , I was speculating ideal attempts given difficulty level similar to 2020 ! Any insights ?
Before getting into the exam hall I became so rigid as to attempt more than 90 , After looking at the paper also I couldnt make up my mind to do anything less than that !
@Aurora A
Correct