@Conquer just count the number of times that these alphabets have appeared in the sequence,
a has been appeared 5 times
similary c has been appeared 4times
and b has been appeared 2 times
hence to make the sequence in logical arrangements we need to append one c and 3 b into this list.hence the answer would be cbbb.
Similarly for this question as well first we need to put e in the last so the initial 4alphabet abab similarly last four alphabet eded are there and the for the rest of the sequence count the number of b d and c you will find b 3 times c 3 times and similarly d 3 times hence we need to have b c d all one times hence answer would be b c d e.
@Shailputri A??
Deleted
@sjerngal D??
@sjerngal D??
