Today’s questions are easy to solve but have to be solved fast. Ideally, take a clock (or use your phone) and try to finish all the problems within 4 minutes. This is practice of your speed, not necessarily your acumen.
The line graph below provides the data pertaining to the fruit production in lakh metric tonnes in various years (between 1991 and 2001). Study and analyze the data carefully and answer the five questions that follow.
Question 1
What is the difference between the highest production and the average production?
(A) 11.5
(B) 9.5
(C) 4.5
(D) 2.7
Question 2
In which of the following years the production is closest to that of average production?
(A) 1991
(B) 1992
(C) 1997
(D) 2000
Question 3
In which period the production registered the sharpest increase over that of the preceding one?
(A) 1993-94
(B) 1995-96
(C) 1997-98
(D) 2000-01
Question 4
What is the difference between the maximum and the minimum production?
(A) 20.6
(B) 19.1
(C) 18.8
(D) 19.5
Question 5
The sharpest decline in production was registered in which period over that of the preceding one?
(A) 1999-2000
(B) 1996-97
(C) 1994-95
(D) 1992-93
N.B. Please note that the official timings for publication of these questions is 11 am daily.
SOLUTIONS TO DAILY CSAT MISSION # 92
1. (A) 2. (D) 3. (B) 4. (D) 5. (C)
Explanations
1. The speed of train = 60 km/hr = 60 x 1000/60 m/min = 1000 m/min.
The length that crosses each point = length of the train = 100 m
So, time taken to cross a point = 100/1000 = 1/10 min = 6 seconds.
2. 3. 4. If 33 people play Kho Kho and Kabaddi, and 12 play Kho Kho, Kabaddi and Volleyball, then the number of people who play Kho Kho and Kabaddi but not Volleyball = 33 – 12 = 21. Similarly, if 30 people play Volleyball and but not Kho Kho = 33 – 12 = 21.
This entire data now can be represented in a Venn Diagram as:
Of the 100 students 10 did not play any of the three games. Hence 90 students played the games. The sum of all the numbers inside the circle should be equal to 90. Therefore, 90 = 9+9+6+21+12+18+ x, which gives x = 15. This is the number of students who can play both Kho kho and Volleyball but not Kabaddi.
Kabaddi people = 21 + 9 +12 + 18 = 60. When the other 10 guys come and join them, the number becomes 70.
Volleyball people = 15 + 12 + 18 + 6 = 51.
If the people common to all the three start resting, then all the three games wil lose the same number of people. The game which had he least number of students earlier will continue to have the least number of students now. It is Volleyball.
5. Let the path walked be representated as:
A————–B————C————–D————E———-F
Given, BE = 80 and BD = 45. So, DE = 35.
Given, CE = 65 and we found DE = 35. So, CD = 30.
Given, BD = 45 and we found CD = 30. So, BC = 15.
Given, AC = 45 and we found BC = 15. So, AB = 30.
Given, DF = 55 and we found DE = 35. So, EF = 20.
The total times taken is the sum of the time taken for every individual part i.e. (30/2.5) + (15/7.5) + (30/12.5) + (35/2.5) + (20/12.5) = 32 seconds.
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