Doubt Clearance Thread: UPSC 2021
"When in doubt, observe and ask questions. When certain, observe at length and ask many more questions."
Created this thread as a one stop solution for all members so that all the doubts wherein any conceptual clarification is required can be solved here.
@sjerngal are they really that bad? they completely shattered my confidence to the point I was thinking of skipping this years attempt
Bhai! DFTBA.
:')
sab yaha jhooth bolm rahe hai, agar himmat hai toh apni real marksheet post karooAap jhootha naam rakh rahe hai! Aap sunnydeol hai, sunnyleony nahin. Himmat aur dhai kilo ki haath ki baat sirf sunnydeol karte hai.
@sstarrr black dp? Protesting something? :D
Not really. What is here to protest? Wanted to change DP , and when nothing struck then went for black background.
Also something related to how I have been feeling in recent days. Not so great , so reflects my state these days.
sab yaha jhooth bolm rahe hai, agar himmat hai toh apni real marksheet post karooAap jhootha naam rakh rahe hai! Aap sunnydeol hai, sunnyleony nahin. Himmat aur dhai kilo ki haath ki baat sirf sunnydeol karte hai.
@sstarrr black dp? Protesting something? :D
Not really. What is here to protest? Wanted to change DP , and when nothing struck then went for black background.
Also something related to how I have been feeling in recent days. Not so great , so reflects my state these days.
Alexa, play 'Sab theek ho jayega' by Biryani Brothers.
Playing 'sab theek ho jayega' by Biryani brothers :D
Similarly for this question as well first we need to put e in the last so the initial 4alphabet abab similarly last four alphabet eded are there and the for the rest of the sequence count the number of b d and c you will find b 3 times c 3 times and similarly d 3 times hence we need to have b c d all one times hence answer would be b c d e.
Why won’t it be c? ababa, bcbcb, and so on?
Yar yeh bta do koi please
sstarrr,
Similarly for this question as well first we need to put e in the last so the initial 4alphabet abab similarly last four alphabet eded are there and the for the rest of the sequence count the number of b d and c you will find b 3 times c 3 times and similarly d 3 times hence we need to have b c d all one times hence answer would be b c d e.
Why won’t it be c? ababa, bcbcb, and so on?
Yar yeh bta do koi please
C hi hona chahiye. You're right.
Similarly for this question as well first we need to put e in the last so the initial 4alphabet abab similarly last four alphabet eded are there and the for the rest of the sequence count the number of b d and c you will find b 3 times c 3 times and similarly d 3 times hence we need to have b c d all one times hence answer would be b c d e.
Why won’t it be c? ababa, bcbcb, and so on?
+1 for C
Villanelle,sstarrr
Similarly for this question as well first we need to put e in the last so the initial 4alphabet abab similarly last four alphabet eded are there and the for the rest of the sequence count the number of b d and c you will find b 3 times c 3 times and similarly d 3 times hence we need to have b c d all one times hence answer would be b c d e.
Why won’t it be c? ababa, bcbcb, and so on?
Yar yeh bta do koi please
C it is !
Villanelle,
Yar yeh bta do koi please
Option C looks right. It forms a pattern. Option d doesn't.
The trick mentioned above fails because here a and e are not equivalent. On completing the sequence there are 3 a's and 2 e's. The sequence is cyclical so the number of letters will match only if we take it to zazaz. Then there will be 5 letters each.
The process in such questions is to
1) count the number of letters in the phrase. The factors of that number are the possible length of the repeating units. Here there are 20 letters. So possible units can be of length 2,4,5 or 10. 2 and 10 can be ignored. So it's either 4 or 5
2) substitute the options and see if there are repeating units of the needed length forming.
This should in most cases give the right answer.
Conquer,thesleepyheadYar yeh bta do koi please
Option C looks right. It forms a pattern. Option d doesn't.
The trick mentioned above fails because here a and e are not equivalent. On completing the sequence there are 3 a's and 2 e's. The sequence is cyclical so the number of letters will match only if we take it to zazaz. Then there will be 5 letters each.
The process in such questions is to
1) count the number of letters in the phrase. The factors of that number are the possible length of the repeating units. Here there are 20 letters. So possible units can be of length 2,4,5 or 10. 2 and 10 can be ignored. So it's either 4 or 5
2) substitute the options and see if there are repeating units of the needed length forming.
This should in most cases give the right answer.
Yep. Right. Thank you :)
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