Question 1
The ages of two people differs by 16 years. If 6 years ago, the elder one was three times as old as the younger one, what are their present ages?
(A) 14 yrs, 30 yrs
(B) 16 yrs, 32 yrs
(C) 8 yrs, 24 yrs
(D) 12 yrs, 28 yrs
Question 2
One morning, James started to walk away from the sun. After 13 km, he turned left and walked 5 km. How far must he walk and in which direction to return back to his starting position?
(A) 12 km North
(B) 12 km North-East
(C) 14 km North-East
(D) 12.5 km East
Question 3
A cube is painted green on all sides, and then is cut into 512 smaller cubes of equal size. How many of the smaller cubes are painted green on one side?
(A) 180
(B) 216
(C) 240
(D) 256
Question 4
Examine the statements given below:
All bureaucrats are engineers.
No bureaucrat is rich.
Which of the following is a valid conclusion that can be drawn from the above two statements?
(A) Some engineers are rich.
(B) No engineer is rich.
(C) All engineers are bureaucrats.
(D) None of these.
Question 5
The proportion of milk and water in three samples is 2:1, 3:1 and 4:1. If a mixture comprising of equal quantities of all three samples is made, what will be the proportion of milk to water in the mixture?
(A) 133:47
(B) 65:25
(C) 7:2
(D) 43:12
SOLUTIONS TO DAILY CSAT MISSION # 59
1.(C) 2.(C) 3.(B) 4.(C) 5.(A)
Explanations
1. The animals in the zoo are either tigers or peacocks.
Let the number of tigers be ‘x’ and the number of peacocks be ‘y’. A tiger has four legs and a peacock two.
So, (x + y) = 60 and (4x + 2y) = 200. This gives y = 20.
2. Original quantity of milk in the mixture = 40 * 3/5 = 24 L.
Original quantity of water in the mixture = 40 * 2/5 = 16 L.
10 L of the mixture will contain 6 L milk and 4 L water.
After first operation, milk = 24 – 6 + 10 = 28 L. Water = 16 – 4 = 12 L.
The ratio of milk and water becomes 28:12. So now, 10 L of mixture will contain 7 L milk and 3 L water.
After second operation, milk = 28 – 7 + 10 = 31 L. Water = 12 – 3 = 9 L.
3. Let the number of people who actually worked be ‘n’. They took 30 days to finish the job.
The total work they put in = 30n.
If there were (n + 8) people , as was the original intention, they would have finished the job in 20 days. So, the work they would have done = 20(n + 8).
Since the work is the same in both situations, 30n = 20(n + 8) which gives n = 16.
4. Volume of the original cube = 8*8*8 = 512. Volume of each smaller cube = 1*1*1 = 1. So, number of smaller cubes = 512/1 = 512.
Surface area of original cube = 6*(8*8) = 384.
Surface area of each smaller cube = 6*(1*1) = 6. Total surface area of the smaller cubes = 512*6 = 3072.
Percentage increase of surface area = [(3072 – 384)/384]*100 = 700%.
5. Discount = 10% of marked price = Rs.28. So, Selling Price = Rs.280 – Rs.28 = Rs.252.
Profit = 26%. Let the Cost Price be ‘CP’. Then, SP = [(100 + Profit %)/100]*CP, i.e. 252 = [(100 + 26)/100]*CP. This gives CP = 200.
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