CSAT 2021 Practice Questions

Will be posting some csat questions for practice here on a daily basis!

Neyawn , CaptainVyom and 12 others like this
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48. The ratio of number of boys and girls who participated in an examination is 4:3. The total percentage of candidates who passed the examination is 80, and the percentage of girls who passed the exam is 90. The percentage of boys who passed the exam is?

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50. There are 2 candidates P & Q in an election. During the campaign, 40% of the voters promised to vote for P and rest for Q. However, on the day of election 15% of the voters went back on their promise to vote for P and instead voted for Q. 25% of the voters went back on their promise to vote for Q and instead voted for P. Suppose P lost by 2 votes, then what was the total number of voters?

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48.

Let number of boys who participated= 4x

Let number of girls who participated =3x

no of candidates who passed the examination= 80% of 7x= (28x/5)
no of girls who passed the examination= 90% of 3x= (27x/10)

So,  no of boys who passed the examination= (28x/5)- (27x/10)= (29x/10)

As %= (29/40)*100= 72.5%

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48.

Let number of boys who participated= 4x

Let number of girls who participated =3x

no of candidates who passed the examination= 80% of 7x= (28x/5)
no of girls who passed the examination= 90% of 3x= (27x/10)

So,  no of boys who passed the examination= (28x/5)- (27x/10)= (29x/10)

As %= (29/40)*100= 72.5%

Correct

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48. The ratio of number of boys and girls who participated in an examination is 4:3. The total percentage of candidates who passed the examination is 80, and the percentage of girls who passed the exam is 90. The percentage of boys who passed the exam is?

boy = 4x ; girl = 3x ;  total = 7x

total passed is 80% => 0.8 * 7x = 5.6x

girls passed is 90% => 0.9* 3x = 2.7x

hence boy passed = 5.6x-2.7x = 2.9x

pass percentage = 2.9x / 4x  =0.725 or 72.5 %

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50. There are 2 candidates P & Q in an election. During the campaign, 40% of the voters promised to vote for P and rest for Q. However, on the day of election 15% of the voters went back on their promise to vote for P and instead voted for Q. 25% of the voters went back on their promise to vote for Q and instead voted for P. Suppose P lost by 2 votes, then what was the total number of voters?

total voter = 100x

                     p             q

 1st eqn       40x           60x

2nd eqn       -6x           +6x

3rd eqn       +15x         -15x

total =       49x             51x

As the final difference between them = 2 (given) = 51x - 49x;

hence x=1; 

total voter = 100.


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BGP said

50. There are 2 candidates P & Q in an election. During the campaign, 40% of the voters promised to vote for P and rest for Q. However, on the day of election 15% of the voters went back on their promise to vote for P and instead voted for Q. 25% of the voters went back on their promise to vote for Q and instead voted for P. Suppose P lost by 2 votes, then what was the total number of voters?

total voter = 100x

                     p             q

 1st eqn       40x           60x

2nd eqn       -6x           +6x

3rd eqn       +15x         -15x

total =       49x             51x

As the final difference between them = 2 (given) = 51x - 49x;

hence x=1; 

total voter = 100.


Correct

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51. 2 pipes A & B can fill a tank in 60 minutes and 75 minutes respectively. There is also an outlet C. If A, B & C are opened together, the tank is full in 50 minutes. How much time will be taken by C to empty the full tank?
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52. 4 Goats and 6 Sheeps can graze a field in 50 days. 2 Goats & 9 Sheeps can graze the field in......... days?
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This is a question from our recruitment test :D

Just to test if people are careless before answering or not


If the sum of age of three people X,Y,Z is 123 years, what was their sum of age 3 years back?

(a) 114

(b) 120

(c) 38

(d) 40

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Neyawn said

This is a question from our recruitment test :D

Just to test if people are careless before answering or not


If the sum of age of three people X,Y,Z is 123 years, what was their sum of age 3 years back?

(a) 114

(b) 120

(c) 38

(d) 40

A

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@Neyawn ideally answer should be cannot be determined....it should have clarified that their ages 3 years prior were  natural number...otherwise 114


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Neyawn said

This is a question from our recruitment test :D

Just to test if people are careless before answering or not


If the sum of age of three people X,Y,Z is 123 years, what was their sum of age 3 years back?

(a) 114

(b) 120

(c) 38

(d) 40

A. 3*3 yrs reduction !

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We will just reduce 3 years of each one's age i.e. 3*3 from the Sum :-)

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Please answer the below Questions wrt this image

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A.

In which year was the value per tin the minimum?

A. 1987

B. 1984

C. 1985

D. 1983

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B. 

If in 1986 tins were exported at the same rate per tin as in 1985, then what would be the value of exports in 1986? (Crores of Rupees)

A. 400

B. 420

C. 375

D. 352

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A.

In which year was the value per tin the minimum?

A. 1987

B. 1984

C. 1985

D. 1983

D
Observation wise- The least difference between the peaks of value and quantity.

Mathematically- 

1983= 1.5

1984= 2

1985= 2.xx

1987= 2.5

upsc2020,
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B. 

If in 1986 tins were exported at the same rate per tin as in 1985, then what would be the value of exports in 1986? (Crores of Rupees)

A. 400

B. 420

C. 375

D. 352

D. 352


cost per unit in 1985= 330/150

in 1986, total units= 160

therefore, total cost= 330/150*160=352

upsc2020,
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